$\sqrt[6]{x^{15}}$
$\frac{\left(20-5^2\right)\left(16+2^2\right)}{-2^3+\left(3\cdot2^2\right)}$
$\left(a^3-2b^2\right)\left(a^3+b^2\right)$
$tan\:g=0.125$
$\lim_{x\to\infty}\left(x^{\frac{x}{5}}\right)$
$\left(2b+7c\right)^3$
$y\cdot y^7$
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