$\lim_{x\to+\infty}\frac{x+4}{3x^2-5}$
$3xy+2xy^2-36xy+35xy^2$
$x+5y=5$
$12a^2-6$
$\left(6x-\frac{5}{4}y\right)^4$
$x\left(a+b+c\right)$
$3cd\left(2c^{12}d^{15}\right)^3$
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