$z^5+1$

$0,125\left(-2\right)\left(-4\right)^{3}\left(4\right)^{2}+\left(-2\right)\left(4\right)$

$\left(6a+5b-8c\right)+\left(5a-5b+4c\right)-\left(2a+3c-5b\right)$

$\int\frac{2x+1}{\left(x-2\right)\left(x-3\right)\left(x+5\right)}dx$

$f\left(x\right)=\left(x^2+3x\right)^2\left(\sin^4\left(x^3+1\right)\right)$

$3=-7+5x$

$5+\left(x^2+5\right)^2+2\left(3x^4+75\right)$