$\int\frac{\sqrt{4x^2+16}}{x}dx$
$\sqrt[3]{-3.375}$
$\int\frac{x-2}{x^2-3x+6}dx$
$3\cdot\left(2-8\right)$
$y^2+6y^3-8+2y^4-3y^2+6y$
$8m^3+16m^2n$
$+\left(-1\right)-\left(+15\right)-\left(-13\right)+\left(+7\right)$
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