$\left(2x\right)\left(\frac{3}{2x}\right)$
$\int12\:x^2\sqrt{4x^3+8}dx$
$13.26+2.78-17.49+6.174-6$
$\frac{dp}{dx}=\left(x+1\right)^2$
$4x-7<3x+8$
$4^3\cdot4^{-1}$
$9y^2-1$
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