$\lim_{h\to0}\:\left(\frac{2\left(1+h\right)^2-2}{h}\right)$

$cos\:2x\:+\:qcos2x\:=1$

$\sqrt[3]{64a^5b^6}$

$\lim_{x\to0}\left(x^{19x}\right)$

$\frac{\left(x^4-2x^3+3x^2-2x+8\right)}{\left(x^2-3x+4\right)}$

$6x^2+19x+3$

$\frac{\left(x^{24}-4\right)}{\left(x^{12}+2\right)}$