$\frac{6x^3}{2x}$
$-x^2+3x-3-3x-3$
$\int_0^{\pi}\left(\sin\left(4x\right)\right)dx$
$3+4-5+6-2-1$
$\lim_{n\to\infty}3\cdot\left(\frac{2}{7}\right)^n$
$y'=y\:\tanh x$
$\left(1-10m^5\right)^3$
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