$\int x^3e^4dx$
$\left(+3-+5\right).-8$
$16+40x^2+25^4$
$0\cdot\left(-10\right)$
$\int\frac{6}{x\left(3-x\right)}dx$
$1x^3+6x^2+11x+6$
$\lim_{x\to-1}\left(\frac{\left(x+1\right)^2}{\sqrt{1+\left(x+1\right)^2}-1}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!