$9x+4^2$
$x^2+4x-7$
$\frac { 2 } { \sqrt { 2 } }$
$\frac{2}{6x^2+11x}$
$\frac{d^3}{dx^3}\left(\sqrt[3]{\left(6x+10\right)}\right)$
$4m+6-32m+48+64$
$\sin^3x-\cos^3x=\left(\sin x-\cos\left(x\right)\right)\left(1+\sin\left(x\right)\cos\left(x\right)\right)$
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