$\left(-5\right)\left(6\right)\left(-3\right)^2\left(7\right)$
$2v^3-3v^2$
$2a\left(4a+2a^2b+3a^2c\right)$
$\infty-1.09$
$\left(8x-4y+2\right)+\left(3x+3y-5\right)$
$x^2-a^2$
$6x-2\cdot6x+2$
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