$\left(-8\right)\:x\:6\:x\:\left(-2\right)$
$\frac{dy}{dx}=3y^2+y$
$\left(-486\right)+\left(+320\right)+\left(-340\right)$
$4x=-8$
$08+\left(13\right)-\left(-53\right)-\left(28\right)$
$-4+9-\left(-7\right)-5$
$x\cdot\frac{dy}{dx}-y=2\cdot\ln\left(x\right)$
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