$2x+5<7x+1$
$16x^2+40x+9$
$3x-13=11$
$1+\tan x+\sec x$
$-\left\{+\left\{6+\left[-\left(7\right)-\left(-12\right)\right]-13\right\}\right\}$
$\int e^x\left(2+e^x\right)^3dx$
$x^2-3x\:+9\:-\:\left(2x^3\:-\:5x^2\:+\:x\:+\:6\right)$
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