$\:3\:-\:\left[4-\:\left(-1\:-\:3\right)\right]$
$\frac{dy}{dx}=-\frac{x}{y^3}$
$\left(4x^2+3x^5-2-3x^2\right)+\left(x^3-3x^2+1-x^2\right)$
$x\sqrt{63y^5}$
$\frac{dx}{dt}=-\frac{x}{t-1}$
$-3-4-6-11+4+8+9-10$
$3x^2+3x-36$
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