$\frac{x^3-x^2+0x+1}{x^2-1}$
$\sec x=-5$
$20x^3+6x^4$
$\frac{dy}{dx}=\frac{xy}{x^2+xy-y^2}$
$8\left(\sqrt[3]{\frac{x}{6}}\right)^2$
$-120+\frac{2x+5z}{x-2yz^2}-45xz\cdot7xyz$
$3ab-bc+3ad-cd$
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