$\lim_{x\to\infty}\left(1+3x\right)^{\frac{1}{x}}$
$\frac{1}{2}\left(8x+2\right)$
$\frac{d^2v}{dx^2}=p$
$\int^3\left(x-1\right)dx$
$\int\left(-\sqrt{3-x}\right)dx$
$\frac{\left(x+2\right)}{2-x}\ge1$
$\frac{6s^3+5s}{3s^2+2}$
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