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Solving: $\frac{d}{dx}\left(-2y=10e^{-3x}\right)$
Solve instead: $\frac{dy}{dx}\left(-2y=10e^{-3x}\right)$

Exercise

$\frac{dy}{dx}\left(-2y=10e^{-3x}\right)$

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Final answer to the exercise

$y^{\prime}=15e^{-3x}$

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