$\lim_{x\to0}\left(\ln\left(1+2x\right)\right)$
$\:\left(b-5\right)^3$
$\frac{dy}{dx}=\frac{cos\:y\:tanx}{-tany}$
$\int_{-1}^1\left(y^3-9y\right)dy$
$\frac{2\cos\left(x\right)\sin\left(x\right)\left(\tan^2\left(x\right)+1\right)}{\tan\left(x\right)}$
$-2\left(x-4\right)=4$
$-x^2+18x+144$
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