$\int_1^{\infty}\left(\frac{x}{x^2+6}\right)dx$
$36=2p\:-12$
$-208-325$
$\left(6-2\right)\cdot3-\left(8-10\right)\cdot4$
$\:\left(35\:x\:3\right)\:+\:\left(105\:x\:7\right)$
$\left(3m^2n-2mn^2+3\right)\cdot\left(m^2n-3mn^2+5\right)$
$\frac{d}{dx}x^2+cy^2=1$
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