$-x^2+5x-4=0$
$\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)+6$
$\left(\sqrt[3]{5}.\sqrt{5}\right)^6$
$a^4\cdot2ba^4$
$\left(6m^3-y\right)\left(6m^3+y\right)$
$\left(3x-1\right)\left(3x+3\right)$
$14x^44$
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