$\left(2a^2\left(x+1\right)\right)^2\left(-3a\left(x+1\right)\right)^3$
$d^2-41=8$
$2z+\left(-10z\right)$
$\left(5+4x\right)^4$
$10.6-7.7$
$\left[-18\:+\:\left(-3+5-7\right).\:\left(-4\right)\:-\:\left(-5+6\right)\::\:\left(-1\right)\right]$
$2^x=a$
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