$\frac{\left(1-tan^2x\right)}{sec^2x}$
$\left(5x-10\right)\left(5x+8\right)$
$\int\frac{x^2-3}{\left(x+1\right)^2\left(x^2+1\right)}dx$
$\frac{dy}{dx}=\frac{2xy}{2x^2+y^2}$
$\left(2a^3+3b^3\right)\left(2a^3-3b^3\right)$
$\sqrt[3]{130-5}$
$-8\left(3u-3y-6\right)$
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