$\left(3x+4y\right)\left(2x-3y\right)$
$5x+1;\:x=3$
$6t\:\left(2t^2\:+\:5t\:+\:8\right)$
$\int\frac{\sqrt{6}+\tan\left(x\right)}{\cos^{2}x}dx$
$\frac{dy}{dx}=\frac{e^{5x}-2}{e^{6x+2y}}$
$\frac{dy}{dx}=2x\cdot e-y$
$\frac{\sqrt{0.25}}{3^{-1}}=\frac{-1.2}{2x-1}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!