$-16+9+1\cdot4^2-1\cdot1^3-1\cdot5^2$

$-x^2-2x+6$

$\int12\cdot\:\left(\frac{1}{12}+\frac{1}{3}x+\frac{1}{4}x^2\right)in\left(x\left(1+x\right)^2\right)dx$

$-9\left(-6\right)\left(2\right)$

$\left(5c+\frac{1}{2}\right)^3$

$\int-6x^{\frac{4}{5}}dx$

$\int2x\cdot\left(x^2+3\right)^4dx$