$60x\:=\:18x$
$\left(2x^3+1\right)^3\left(x^2\right)$
$6x^2+x-2=0$
$\frac{9}{5}\left(3-x\right)$
$\int-6e^{3x+1}dx$
$-7\:.\:1\:+\:4$
$\int\left(x^2\sqrt{9-4x}\right)dx$
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