$\frac{d}{dx}\sqrt{10x-7}$
$\left(5x-4y^3\right)^2$
$\arccos\left(\cos\left(\frac{6\pi}{7}\right)\right)$
$\left(\frac{5}{2}x^{2a}+\frac{2}{3}x^{3-5a}\right)^{3}$
$-x^2=-3x-18$
$\frac{x^2+2x-4}{x^2}$
$\frac{\sin x-\sin^3x}{\cos^3x}=\tan x$
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