$\lim_{x\to\infty}\left(\frac{ln\left(x\right)}{x^{-2}}\right)$
$\left(4-4\right)^2+\left(3+2\right)^2$
$24x+9=-16x^2$
$-\left(3x^2+5\right)\left(3x^2-5\right)$
$\frac{6x^4+12x^3+12x+3}{x-6}$
$\left(-8\right)-\left(-169\right)$
$x+8x+3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!