$x^3+y^3=36$
$\frac{23}{0.37}$
$\frac{dy}{dx}=100+700\sqrt{x}$
$6b-2b-3a$
$\left(-2\right)^1.\left(-2\right)^3.\left(-2\right)^4$
$\int_1^{1.2}\left(c^x\right)dx$
$\int16x^3\sqrt[3]{4x^4-4}dx$
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