$\frac{6x^2+8x+10}{x^3+2x^2+5x}$
$2\cos\left(1\right)+1=0$
$\left[\left(-12\right)-\left(-20\right)\right]-\left[\left(6\right)+\left(5-9\right)-\left(16-8-11\right)\right]$
$\frac{3x^2+16x+21}{x+4}$
$\left(x+2\right)+3$
$20^6$
$6^2+2\cdot6\cdot4+4^2$
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