$\int\frac{\left(z^2+1\right)^2}{\sqrt{z}}dz$
$x^2-6x+9\ge0$
$7\left(z-4\right)+8z-1$
$\int\left(64x-48x^3+12x^5-x^7\right)dx$
$-2-4+8+4-6+7-2+9-5$
$4\left(4x\:-\:3y\right)$
$\frac{dy}{dx}=4x\ln\left(1-x^2\right)$
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