$2x+2ux$
$\int\frac{-x^3+3x-5}{x\left(2-x\right)^3}dx$
$4\left(1+2y\right)$
$x^2+4x-5x-20$
$4.x=-24$
$\left(-20v^3w^2\right)-\left(12.3v^3w^2\right)$
$\tan\left(\arctan\left(\frac{-3}{4}\right)+\arctan\left(\frac{1}{4}\right)\right)$
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