$\frac{6^4}{6^3}$
$\lim_{x\to0}\:\frac{cotx}{ln\left(4x+1\right)}$
$-234\cdot8$
$2x+6=14$
$6x^2-x-5=0$
$\int\left(x^{\frac{3}{2}}+5\right)^4\sqrt{x}dx$
$\frac{d^3}{dx^3}\left(2+3x\right)^3$
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