$+0.5-4.7$
$\int\frac{2}{x^3+8}dx$
$\frac{n}{8}-3=-11$
$\left(\frac{3}{1}\right)\left(\frac{2}{3}\right)^2\left(x\right)$
$x+\frac{1}{x}=\frac{x^2+1}{x}$
$3x^2-6x-5=0$
$9+-11\:+17\:+17\:+-5\:+6+-1+7$
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