$\left(1+3a\right)\left(x-1\right)-2a\left(x-1\right)+3\left(x-1\right)$
$6x^2-x-5=0$
$\frac{dy}{dx}=\frac{2x^2}{3x^2+4}$
$\left(x^3+3xy^2\right)^3$
$xy'+2y=\sec x$
$\left(+7\right)-\left(+3\right)\cdot\left(-4\right)$
$2b+2c$
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