$3x-5;\:x=7;\:x=4$
$x^{2\:}+19x+12=\left(4x+3\right)\left(x+4\right)$
$\left(3h-2\right)^3$
$\int4\left(6x+1\right)^5dx$
$\lim_{x\to0}\left(\frac{e^{-x^2}}{x^2}\right)$
$\frac{2}{5}.\frac{15}{4}\cdot2\frac{1}{3}\cdot1$
$25y+12y-31y-8y+5y$
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