$\int\left(tan\left(x+3\right)\right)dx$
$8y^2+4y+1-\left(2y^2-7y-1\right)$
$\left(9x^2+5y^2\right)\left(9x^2-5y^2\right)$
$\int\:\:\:10\left(x+1\right)\left(x^2+2x+3\right)^4\:dx$
$36x^2-100=0$
$4y'-2xy$
$0=\frac{x+3}{7x-28}-\frac{6}{x-4}-\frac{2}{7}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!