$5x^{\frac{3}{1}}$
$\frac{dy}{dx}\:+\:\frac{y}{x}\:=1$
$\frac{x^2+6x+9}{2x+1}$
$3x\left(2x^2-5x+1\right)$
$3b+9b^2$
$\frac{2e^xe^y}{\left(e^x+e^y\right)^2}$
$\lim_{x\to\infty}\left(\frac{\left(5x+9\right)}{6x^2+7x-8}\right)$
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