$2+3-5+4-6+3-8-2+4-2$
$4\cdot3+4$
$x^2-5x\le-6$
$\left(3\tan^2\left(x\right)-1\right)\left(\tan^2\left(x\right)-1\right)=0$
$\int_0^{\frac{\pi}{2}}\left(5xcosx\right)dx$
$\int4tan^2\left(x\right)dx$
$64^3:4^4$
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