$3k^25k$
$\frac{3x^2-3x+9}{x^2-6x-7}<3$
$abx2\:-\:ax3\:+\:bx$
$\left(\frac{1}{2}m^4-\frac{1}{4}n^4\right)^3$
$x\:=\:\frac{\left(e^{4y}\right)}{z^5}$
$\frac{81m^6-49n^4}{9m^3+7n^2}$
$\frac{-5}{7y}+\frac{4}{3y^2}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!