$\int\frac{-9}{x^3-1}dx$
$\frac{d}{dx}y^2=\frac{2a^3x}{x^2+a^2}$
$\left(3x+8y\right)\left(2x+4y\right)$
$3x-9x+1$
$\sin^3\left(x\right).\csc^2\left(x\right).\cot\left(x\right)$
$4+x\frac{dx}{dt}=x^2+1$
$\int\left(x^4-1\right)x^2dx$
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