$\left(x^2+4\right)dy\:-xy\:dx\:=\:0$
$6\cdot\left(5+2\right)$
$8x\:-\:8y\:+\:3x\:-\:5y\:-\:4x\:+\:5x$
$\int\frac{10x+8}{x^2-49}dx$
$\frac{1}{\sec\left(a\right)-1}-\frac{1}{\sec\left(a\right)+1}=2\cot^2\left(a\right)$
$12x^2-4$
$\frac{dy}{dx}=\:2x+1;\:y\left(0\right)=3$
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