$\left(\frac{6x^2}{5}-\frac{3\sqrt{3}y^3}{4}\right)^2$
$3x+2>\frac{1}{3}-x$
$\frac{14}{2}$
$\int\frac{16}{x^2+2x-15}dx$
$7.35\:\cdot\:10-8\:n$
$3\sqrt[3]{i}+\left(-\sqrt[3]{i}\right)+3\sqrt[3]{i}+\left(-\sqrt[3]{i}\right)$
$\frac{x-1}{\sqrt[3]{x-1}}$
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