$sec^4\left(x\right)-sec^2\left(x\right)=tan^4\left(x\right)+tan^2\left(x\right)$
$\frac{dy}{dx}=\frac{x^2}{y+1}$
$\int4x^2\left(x^3+8\right)dx$
$\left(3^4\right)^5$
$3c+c$
$\frac{3}{5a}+\frac{2}{3a}$
$5a-5a^2-10a^4$
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