$-34-\left(-25\right)$
$\lim_{x\to\infty}\left(\frac{\sqrt[3]{8x^6-8}}{x^2+4}\right)$
$478-1500\cdot1\cdot2^0\cdot\left(-3\right)^0$
$\left(12\right)^3$
$1.05x+6y-8=0$
$\int\frac{3x}{x^2-16}dx$
$\left(-5-2i\right)-\left(3-3i\right)$
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