$\left(3x\right)\left(-24xy\right)$
$20x^2-25x-800$
$\int\sec\left(x\right)\left(\tan\left(x\right)-\sec\left(x\right)\right)dx$
$\left(-12a^2b^3\right)\left(5a^2b^2\right)$
$\frac{1}{\sec^3\left(x\right)}$
$\frac{4x^2+12x+12}{2x+3}$
$\int\:\left(3x+1\right)\left(2x-5\right)^5dx$
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