$\lim_{m\to5}\:\frac{m^2-25}{m+5}$

$y=\frac{dy}{dt}$

$\ln\left(\cosh\left(4x-\sinh\left(4x\right)\right)\right)+\ln\left(\cosh\left(2x\right)-\sinh\left(2x\right)\right)$

$1\frac{\tan^2\left(x\right)}{1+\sec\left(x\right)}=\sec\left(x\right)$

$\frac{dy}{dt}=\frac{y+3}{1-y}$

$\lim_{n\to\infty}\left(\frac{5n^2}{n+1}\right)$

$\frac{d}{dx}20\sqrt{x}$