$3a^2\cdot6ab$
$22x-20>40-8x$
$28-8x+3x$
$\int\left(\frac{ln12x}{x^2}\right)dx$
$\int\frac{u-8}{u^2-2u-8}du$
$-4732+-3269$
$g^4x-5g^4x^2-g^4x-3g^{-4}x^2$
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