$-497\cdot100$
$\frac{dx}{dy}+x+\frac{2x}{y}=\frac{1}{y^2}$
$\frac{1}{a^3-16}+\frac{3}{a^3-16}+\frac{a}{a^3-16}$
$\int x\left(x-2\right)\left(x+2\right)dx$
$4\frac{\left(2\right)^2}{\left(2\right)}$
$\frac{dy}{dx}=-y+6$
$\left(9a^3b^4c\right)\left(-3a^4bc^2\right)$
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