$0+8-\left(6\cdot4\right)+2$

$\left(y^3-4y+1\right)\left(y+2\right)-\left(-2y^2+3\right)$

$sin\left(90^{\circ\:}+\theta\:\right)=cos\theta\:$

$25x^2-36y^8$

$2\left(3\sqrt{2}\right)^2$

$\frac{\left(\frac{-4}{3}\right)-\left(\frac{-3}{-4}\right)}{1+\left(\frac{-4}{3}\right)\left(\frac{-3}{-4}\right)}$

$^{\frac{x^8-\:y^{3b-2}}{x-y^{b-4}}}$