$\int\left(\frac{x}{\left(4x-x^2\right)^{\frac{3}{2}}}\right)dx$
$x\:2\:-\:x\:-\:72\:=\:$
$\left(3g\right)\left(12^{-1}g^3\right)\left(2g^{-1}\right)$
$\left(2a+4b+2c\right)+\left(c-3a+2b\right)$
$3x^2-18x+3$
$-2x-3x^2-5=-1$
$-4\:\:=\:_{2\:}$
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