$\sqrt{3x}x^2$
$1x^{10}+3x+1$
$\frac{9x^3+6x^2+3x+10}{3x^2+2}$
$13.5\cdot13.5$
$12+\left(65\cdot6\right)$
$\left(6x-8\right)\left(6x+3\right)$
$4\left(a^3\right)^5$
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